AMCAT( Aspiring Minds Questions and Solutions)

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Who is fastest among the X,Y,Z

1)X AND Y PAINTS ROOM IN 12 MINS

2)X,Y, AND Z PAINTS ROOM IN 17 MINS

A)STATMENT 1 IS SUFFICIENT

B)STATMENT2 IS SUFFICENT

C)BOTH STATMENTS ARE SUFFICIENT

D)BOTH ARE NOT SUFFICIENT --->

1)X AND Y PAINTS ROOM IN 12 MINS

2)X,Y, AND Z PAINTS ROOM IN 17 MINS

A)STATMENT 1 IS SUFFICIENT

B)STATMENT2 IS SUFFICENT

C)BOTH STATMENTS ARE SUFFICIENT

D)BOTH ARE NOT SUFFICIENT --->

product of two successive numbers is
4692. Which is the smaller of the two numbers?

1)69 2)62 3)68 4)67 5) None of these

1)69 2)62 3)68 4)67 5) None of these

To fill a storage tank of wheat ,20
containers full of wheat are required.how many containers of wheat will be
required to fill same tank.if the capacity of tank is reduced to two-fifth of
their present capacity??

1)25

2)30

3)60

4)50

1)25

2)30

3)60

4)50

what is sum of two consecutive
numbers. if the squares of their difference is 19

a)9

b)10

c)18

d)19

a)9

b)10

c)18

d)19

To fill a storage tank of wheat ,20
containers full of wheat are required. how many containers of wheat will be
required to fill same tank.if the capacity of tank is reduced to two-fifth of
their present capacity??

1)25

2)30

3)60

4)50

1)25

2)30

3)60

4)50

At an election there are five
candidates among which three are to b elected and a voter can vote to any
number of candidates not greater than number of candidates to be elected.the
number of ways in which a voter can vote??

1)25

2)32

3)30

4)none of these

1)25

2)32

3)30

4)none of these

1. Find the odd no: 2,3,12,36,86,167

Sol:
given series. 2,3,12,36,86,167

now, 3-2=1 => 1^2=1; 12-3=9 => 3^2=9;

now, 3-2=1 => 1^2=1; 12-3=9 => 3^2=9;

36-12=24 => here if we change 36 into 37 then 37-12=25 =>5^2=25

86-36=50 => Similary 86-37=49 =>7^2=49

167-86=81 =>9^2=81

so answer will be 36.

86-36=50 => Similary 86-37=49 =>7^2=49

167-86=81 =>9^2=81

so answer will be 36.

2.
8,12,24,60,... what is the next number?

Sol:
12-8=4; 24-12=12; 60-24=36...

the difference like this 4*3=12,12*3=36 then next 36*3=108.so the answer is 108+60=168.

the difference like this 4*3=12,12*3=36 then next 36*3=108.so the answer is 108+60=168.

3. 3,7,10,11,12,17,? find out next
number?

Sol:
sum of alternates -1 equal to next alternate number.

3+10-1=12; 7+11-1=17; so the next number will be 10+12-1=21

3+10-1=12; 7+11-1=17; so the next number will be 10+12-1=21

4. Cost price of 4 calculators and 2
pencil is 6200. What is the cost of ten calculators and five pencils.

Sol: C+2P=6200-->2C+P=3100

SO 10C+5P=5(2C+P)=5(3100)=15,500 RS

SO 10C+5P=5(2C+P)=5(3100)=15,500 RS

5. 12 men can complete work in 6 days whereas
10 men and 21 women take 3 days to finish the same work .in how many days can
12 women alone complete.

Sol:
10 men's, 1 day work=10/(12*6)=5/36

If 21 women's, 1 day work= 21/W ,then

3[(5/36)+(21/W)]= 1 ,On solving, W=108

So, 12 women can complete the work in 108/12=9 days

If 21 women's, 1 day work= 21/W ,then

3[(5/36)+(21/W)]= 1 ,On solving, W=108

So, 12 women can complete the work in 108/12=9 days

6. 27

^{18}/14 find the remainder value?
Sol: Any number of the form (a*x-1)^n /a
the remainder will be +1 if the power n is even.

and the remainder will be -1 or (a-1) if
the power is odd. According to this the remainder will be 1

7. What is the probability of getting a
odd sum when two dice are thrown.

Sol: odd numbers 3,5,7,9,11(between
2(min sum)-12(max sum))

cases:- 3-(1,2),(2,1) 5-(3,2),(2,3),(4,1),(1,4) 7-(1,6),(6,1),(2,5),(5,2),(3,4),(4,3)

9-(3,6),(4,5),(5,4),(6,3) 11-(5,6),(6,5)

cases:- 3-(1,2),(2,1) 5-(3,2),(2,3),(4,1),(1,4) 7-(1,6),(6,1),(2,5),(5,2),(3,4),(4,3)

9-(3,6),(4,5),(5,4),(6,3) 11-(5,6),(6,5)

total cases=18 therefore
probability=18/36=>1/2

8. If log(p+q)(p-q)= -1; then find the value of:
log(p+q)(P

^{2}-q^{2})
Sol: log(p+q)(p

^{2}-q^{2})=log(p+q)^{2}(p-q)=log(p+q)^{2 }+ log(p-q) = 2 log(p+q) + log(p-q) = log(p+q)+log(p+q)+log(p-q)
log(p+q)-1=
log(p+q)-log 10= log (p+q)/10;

9. If peacock = 11526312316 then
feather=

Sol: First letter is decoded on the
position of letter in reverse order

and 2nd letter is decoded on the position of letter in alphabetic order in peacock

p=11 e=5 a=26 c=3 o=12 c=3 k=16

so, feather

and 2nd letter is decoded on the position of letter in alphabetic order in peacock

p=11 e=5 a=26 c=3 o=12 c=3 k=16

so, feather

f=21 e=5 a=26 t=20 h=19 e=5 r=9

Ans: 21526201959

10. Find the number of consecutive zeros
at the end of 72!

Sol: By using formula round(n/5)+round(n/25)+..........round(n/5^n)

round(72/5)+round(72/25)=14+2=16

11. Find the maximum value of n such
that 77! is perfectly divisible by 720^n

Sol: 720 = (2^4) x (3^2) x (5)

Number of twos in 77! is: 38 + 19 + 9 + 4 + 2 + 1 = 73

So number of 2^4 will be: = 18

Similarly, Number of threes in 77! is:

25 + 8 + 2 = 35

So number of 3^2 will be: = 17

and number of fives will be:

= 15 + 3 = 18

Hence the number of 720s that we can obtain is 17.

Number of twos in 77! is: 38 + 19 + 9 + 4 + 2 + 1 = 73

So number of 2^4 will be: = 18

Similarly, Number of threes in 77! is:

25 + 8 + 2 = 35

So number of 3^2 will be: = 17

and number of fives will be:

= 15 + 3 = 18

Hence the number of 720s that we can obtain is 17.

12. Some persons can do a piece of work in 12 days. Two
times the number of such persons will do half of that work in:

Sol: 3 days

13. If log

_{10}2 = 0.3010, what is the number of digits in 2^{64}
Sol: 2

Characteristic(integral part of log) is one less than no. of digits. here characteristic=19; So no of digits=19+1.

^{64}= 64 log2=64*0.3010=19.264Characteristic(integral part of log) is one less than no. of digits. here characteristic=19; So no of digits=19+1.

14. log

_{y}1369y=3 then what is the value of y?
Sol: y

^{3}=1369y y^{2}=1369 y=37
15. 4.28 and -3.28 are two numbers on a
real number line. If 1 is added to both the numbers ,then which of

the following is true?

a.Distance between the two numbers is 2
units more than the distance between 4.28 and -3.28

b.Distance between the two numbers is 2
units less than the distance between 4.28 and -3.28

c.Distance between the two numbers is
equal to than the distance between 4.28 and -3.28

d.None

Ans:c

distance b/w 4.28 and -3.28 = 7.56

distance b/w 5.28 and -2.28 = 7.56

distance b/w 5.28 and -2.28 = 7.56

16. What is the greatest 4-digit perfect
square, which is exactly divisible by 3, 5, 7 and 9?

a. 9999 b.
9684 c. 9801 d. Cannot be determined e. 11025

17. What is the full form of OSI ?

Ans: Open system interconnection

18. What is the remainder when 17

^{23}is divided by 16?
a. 1 b.0 c.2 d.3

Sol:
Apply bionomial theorem. 17 can be written as (16+1)

similarly 17

^{23}= (16+1)^{23}
expand above equation using bionomial
theorem then we get 24 terms, in that 23 terms contain 16

^{x}as one term for x>0; 24th term will be 24c_{24}1^{24}=1 when you divide 1 with 16 you get 1 as remainder.
19. antilog10

^{100}
Sol: All you need to know is that AntiLog(X) = 10

^{x}.
so ans is 10^(10

^{100})
20. Four bells begin to toll together
and then each one at intervals of 6 s, 7 s, 8 s and 9 s respectively. The

number of times they will toll together
in the next 2 hr is:

Sol: lcm of 6,7,8,9=504 sec; in 2
hrs =3600*2 sec

so no times they will ring
=3600*2/504==14 times

21. The students are in the ratio
2:3:5.if 20 students are increased in each batch the ratio changes to 4:5:7

The total number of students in the
three batches before the increase was

Sol: Let number of students be x

2x+20 : 3x+20 : 5x+20 = 4:5:7 --> x = 10

Initially the number of the students would be 20,30 and 50 --> 100 ans

2x+20 : 3x+20 : 5x+20 = 4:5:7 --> x = 10

Initially the number of the students would be 20,30 and 50 --> 100 ans

22. sum of money doubles itself in 9
years, in how many years it will become 8 times itself?

Sol: 27 years; 9yrs = 2(sum); 18yrs = 4(sum); 27yrs = 8(sum)

23. What is the smallest four-digit
number which when divided by 6, leaves a remainder of 5 and when

divided by 5 leaves a remainder of 3?

1. 1043 2.
1073 3. 1103 4.None of these

Sol: ans is none of these because :

let us assume the smallest 4 digit number be 1000 if we divide it with 6 we get remainder 4 so to get a rem of 5 add 1 to it => 1001.

Then the general form of a number is 1001+6k for every positive integer value of k it always yields rem 5 when divided by 6

then by trail and error if we take k=2 then number is 1013

which when divided by 5 gives a rem of 3

so the right ans is 1013 which is none of these from options

let us assume the smallest 4 digit number be 1000 if we divide it with 6 we get remainder 4 so to get a rem of 5 add 1 to it => 1001.

Then the general form of a number is 1001+6k for every positive integer value of k it always yields rem 5 when divided by 6

then by trail and error if we take k=2 then number is 1013

which when divided by 5 gives a rem of 3

so the right ans is 1013 which is none of these from options

24. A, B, C started a business with
their investments in the ratio 1:3:5. After 4 months, A invested the double amount as before and B as well as C withdrew
half of their investments. The ratio of their profits at the end of the year
is:

Sol: Let their initial investments be x,
3x and 5x respectively. Then,

A : B : C = (x * 4 + 2x * 8) : (3x * 4 + 3x/2 * 8 ) : (5x * 4 + 5x/2 * 8)

= 20x : 24x : 40x = 5 : 6 : 10.

A : B : C = (x * 4 + 2x * 8) : (3x * 4 + 3x/2 * 8 ) : (5x * 4 + 5x/2 * 8)

= 20x : 24x : 40x = 5 : 6 : 10.

25. There are 10 yes or no questions.
How many ways can these be answered?

Sol: for 1 question 2 possibilities

for 2nd question 2 possibilities

for 3rd question 2 possibilities

.

.

..

.

2

for 2nd question 2 possibilities

for 3rd question 2 possibilities

.

.

..

.

2

^{10}=1024
26. In an examination, 70% of students
passed in physics, 65% in chemistry, 27% failed in both subjects. The
percentage of students who passed is:

1. 66% 2.
62% 3. 69% 4. None of these

Sol: let's total student be 100

Passed in atleast one subject= 100-27=73.

73= 70+65-x(passed both subjects)

Passed in atleast one subject= 100-27=73.

73= 70+65-x(passed both subjects)

x=62.

27. If the simple interest on a sum at
4% per annum for 2 years is Rs. 80, then the compound interest on the same sum
for the same period is:

1. Rs. 86.80 2. Rs. 86.10 3. Rs. 88.65 4. Rs. 81.60

Sol: S.I for 2 years is 80;

Then S.I for one year is 40. C.I for 2 years = S.I for 2 years + S.I
for 40

=80+(40*4*1)/100=80+1.60=81.6

28. Prabodh bought 30 kg of rice at the
rate of Rs. 8.50 per kg and 20 kg of rice at the rate of Rs. 9.00 per kg. He mixed
the two. At what price (App.) per kg should he sell the mixture in order to get
20% profit?

1. Rs. 9.50 2. Rs. 8.50 3.
Rs. 10.50 4. Rs. 12.00

Sol: 30*8.5+20*9=435

20% of 435 is 87

total= 435+87=522

522=50*x; x=10.44= 10.5(approx)

29. Mohan walks a certain distance and
rides back in 6 hours and 15 minutes. If he walks both ways he takes 7 hours
and 45 minutes. If Mohan rides both ways the time which he will take will be:

1. 4 hours 2. 19/4 hours 3.
9/2 hours 4. 17/4 hours 5. None of these

Sol: W+R=375 minutes(6 hours 15 minutes)

2W=465 minutes(& hours 45 minutes)

2R=?

2(W+R)=375*2=750

2R=750-465=285=19/4

2W=465 minutes(& hours 45 minutes)

2R=?

2(W+R)=375*2=750

2R=750-465=285=19/4

30. In an examination 10 questions are
to be answered choosing at least 4 from each of part A and part B. If there are
6 questions in part A and 7 in part B, in how many ways can 10 questions be
answered ?

1. 212
2. 266 3. 272 4. 312
5. Correct Op

Sol: 266 = 6c4*7c6+6c5*7c5+6c6*7c4

31. A boy move 6 m in west then he turn
towards south and move 20 m then turn towards east and move 12 m again move
toward north and move 12 m . How much dist he is away from his starting point.

Sol: sqrt(8^2+6^2)=10

32. synonym of OBTRUSIVE

Sol: conspicuous

33. hcf of 3.68 & 5.35

Sol: prime factorization of 368 is 2

^{4}*23
prime factorization of 535 is 5*107

hcf is 1. ans is 0.01

34. 3*(4

^{4}+4^{3}+4^{2}+4+1) = ?
Sol: 3*(4

^{5}-1)/4-1 ( applying sum of n terms in G.P )
=4

^{5}-1= 1023
35. log

_{10}2=.6096 log_{10}3=.4709 then log_{10}12 = ?
Sol: log

_{10}12= log_{10}(2^{2}*3)= log_{10}2^{2}+ log_{10}3= 2 log_{10}2+ log_{10}3=2*0.6096+0.4709= 1.6901
36. log xy - log
|x| = ?

Sol: log xy -
log |x| = log x + log y - log |x| = log y

since x > 0 for log to be defined.

hence |x| = x

since x > 0 for log to be defined.

hence |x| = x

37. log

_{25}625 - log_{31}961 + log_{29}841 =?
Sol: 2-2+2=2

38. P3M : N4J
:: R3P :
??

Sol: because compare P3M with R3P then
N4J=P4M

39. 2,35,104,209,?

Sol: 35-2=33;104-35=69;209-104=105;;

69-33=36;105-69=36;;

so 36+105=141==>>141+209=350(ans)

69-33=36;105-69=36;;

so 36+105=141==>>141+209=350(ans)

40. NATION - 1412091514 THEN REMOTE- ?

Sol: Ans: 1851315205

A=1 B=2 ...................Z=26

A=1 B=2 ...................Z=26

41. product of two no u and v is 42.

conclusion

1.u is less than v

2. u is even.

options:

1. conclusion 1 and 2 both are necessary

2.only one is sufficient.

3.only two is sufficient

4. data not sufficient

Sol: Data not sufficient why because....

2*21

3*14

6*7 are the possibilities.

u is even means u can be 2,14,6 and u less than v again two possibilities are there.... 2*21 and 6*7... so data in sufficient.

2*21

3*14

6*7 are the possibilities.

u is even means u can be 2,14,6 and u less than v again two possibilities are there.... 2*21 and 6*7... so data in sufficient.

42. how many 5 digit nos are possible
from 2,7,0,8,4 if the first digit is not zero

Sol: if there is no repetition then its
equal to=4*4*3*2*1=96

if repetitions are allowed = 4*5*5*5*5=2500

if repetitions are allowed = 4*5*5*5*5=2500

43. 400 have how many factors?

Sol: 15 factors....

400=2

no of factor=5*3=1

400=2

^{4}*5^{2}no of factor=5*3=1

44. A box contain 6 yellow,3 red and 2
green ball 5 ball is randomly selected what is the probability that at least
one ball is yellow.

Sol: probability=at least 1 ball yellow

=1-no ball yellow

=1-{(6C0*3C3*2C2)/11C5}

=1-(1/462)

=0.997

=1-no ball yellow

=1-{(6C0*3C3*2C2)/11C5}

=1-(1/462)

=0.997

45. if north-west is east ,north-east is
south then what is east?

Sol: south-west

46.How many two digit numbers have
exactly 5 factors?

Sol: for a two digit number to have 5
factors it must be a squared number and it must not be a square of prime
number. the two numbers are,

4^2 = 16 = 1,2,4,8,16

9^2 = 81 = 1,3,9,27,81

4^2 = 16 = 1,2,4,8,16

9^2 = 81 = 1,3,9,27,81

47.How many four digit numbers have
exactly 5 factors?

Sol: for any no. greater than 100 to
have 5 factors it must be the 4th power of the prime number.

e.g, 5^4 = 625 = 1,5,25,125,625

7^4 = 2401 = 1,7,49,343,2401

11^4 = 14641 = 1,11,121,1331,14641

so the only 4 digit number having 5 factors is 2401

and two digit number having 5 factors are 16 and 81

e.g, 5^4 = 625 = 1,5,25,125,625

7^4 = 2401 = 1,7,49,343,2401

11^4 = 14641 = 1,11,121,1331,14641

so the only 4 digit number having 5 factors is 2401

and two digit number having 5 factors are 16 and 81

48. 15?1792 is divisible by 9 only when
?=

1.1 2.4. 3.3. 4.2.

Sol: 1+5+1+7+9+2=25=2+5=7+?=9 so ?=2

49. 2

^{x+y}=2/2^{3/2}; 2^{x-y}=2; Find the values of x and y?
Sol: 2

and 2

and x=1/4 y=-3/4

^{x+y}=2^{1-3/2}; x+y=-1/2;and 2

^{x-y}=2^{1}; x-y=1;and x=1/4 y=-3/4

50. 6,9,__,24,39. 1).18. 2)15. 3).10. 4)12.

Sol: its simply the addition of the
previous two numbers

9+6=15; 15+24=39; so the answer is 15

9+6=15; 15+24=39; so the answer is 15

51. GULMOHAR=TFONLSZI..... then PIPAL
=??

Sol: GULMOHAR = TFONLSZI

G+T = 7+20 = 27

U+F = 21+6 = 27

.....

A+Z = 1+26 = 27

R+I = 18+9 = 27

So,

27-P = 27-16 = 11 = K

27-I = 27-9 = 18 = R

27-P = 27-16 = 11 = K

27-A = 27-1 = 26 = Z

27-L = 27-12 = 15 = O

PIPAL = KRKZO

G+T = 7+20 = 27

U+F = 21+6 = 27

.....

A+Z = 1+26 = 27

R+I = 18+9 = 27

So,

27-P = 27-16 = 11 = K

27-I = 27-9 = 18 = R

27-P = 27-16 = 11 = K

27-A = 27-1 = 26 = Z

27-L = 27-12 = 15 = O

PIPAL = KRKZO

52. 79,64,26,15,__

Sol: 79= 7*9 = 63+1= 64

64 = 6*4 = 24+2= 26

26= 2*6 = 12+3 = 15

15 = 1*5 = 5+4 = 9

so the ans is 9

64 = 6*4 = 24+2= 26

26= 2*6 = 12+3 = 15

15 = 1*5 = 5+4 = 9

so the ans is 9

53. 8,8,6,2,___.

1.-4. 2.4 3.2 4.0.

Sol: 8-8 = 0; 8-6 = 2; 6-2
= 4; 2-(-4) = 6; So Ans is: -4

54. Please remember all the words
because amcat always repeat synonym and
antonym...

1.conceit 2.conceal 3.preamble 4. Engendered 5.veteran 6..instigate 7.blighting

8.overt 9.verdict 10.avarice 11.set off 12.
gruesome 13.vent

these words were in my set and my friend
set so prepare the synonym and ant both because
when they repeat question they change ant into synonym or vice
versa.....

Sol:
Synonyms : 1.arrogance 2.hide 3.preface 4.arouse,create,stir 5.experienced,old time

6.influence,provoke 7.ruin,destroy 8.unconcealed 9.judgement 10.greedy 11.compensate, redeem

12.horrible, awful 13.outlet

6.influence,provoke 7.ruin,destroy 8.unconcealed 9.judgement 10.greedy 11.compensate, redeem

12.horrible, awful 13.outlet

Antonyms: 1.humility,shyness 2.disregard,uncover,disclose 3.discusion,meeting 4.calm, destroy, discourge

5.unskilled, inexperenced 6.discourage, negelect 7.Encourage, improve 8.unclear, hidden

9. announcement, commitment 10.generosity, philanthopy 11.disagree, spoil

12.attrective, beautiful 13.closing, clouse

5.unskilled, inexperenced 6.discourage, negelect 7.Encourage, improve 8.unclear, hidden

9. announcement, commitment 10.generosity, philanthopy 11.disagree, spoil

12.attrective, beautiful 13.closing, clouse

55. 6 years back, Rom and Dom had their
ages in the ratio 1:2. 6 years from now the ratio of their ages would be 3:4.
What is the ratio of their ages today?

Sol: (x-6)/(y-6)=1/2 ....(1)

(x+6)/(y+6)=3/4 ..(2)

by solving these eqn, we get x=12 and y=18 i.e. 2/3

(x+6)/(y+6)=3/4 ..(2)

by solving these eqn, we get x=12 and y=18 i.e. 2/3

56. A locomotive engine, without any
wagons attached to it, can go at a speed of 40 km/hr. Its speed is diminished
by a quantity that varies proportionally as the square root of the number of
wagons attached. With 16 wagons, its speed is 28 km/hr. The Op 1: 99 Op 2: 100
Op 3: 101 Op 4: 120 Op 5:

57. If 33 untrained labourers can do a
work in 15 days of 12 hr. each, how many trained labourers can do 50% more work
in 11 days of 9 hr each ? (It may be assumed that it takes 2 trained labourers
to do the work of 5 untrained labourers) Op 1: 42 Op 2: 36 Op 3: 90 Op 4: 100
Op 5:

Sol: 5u=2t
u=2/5t

(33*2t*15*12)/(5*xt*11*9)=2/3

x=36 op 2:36

(33*2t*15*12)/(5*xt*11*9)=2/3

x=36 op 2:36

58. |X - 5| + 4 > 0 and |X2| < 4.
Then x can be: Op 1: 4 Op 2: 2 Op 3: 0.5 Op 4: All of these Op 5:

Sol: Op 3: 0.5; 4.5+4>0; &(0.5)^2

59. If r = at

^{2}and s = 2at, the relation among s, r and a is: 1. s^{2}=4ar 2. s=ar 3. s=2ar 4. s^{2}=ar 5. None of these
Sol:
s=2at; squaring on both
sides; s

^{2}=4a^{2}t^{2}=4a* at^{2}=4ar; so option 1 is correct
60. If |x| + |y| = 7, then what is the
sum of minimum and maximum values of x + y? 1. 3/2 2. -7 3. 7 4. 0 5.none

Sol: 0; as
mod has property; |x|=x;x>0; =-x;x

61. If x

^{4}+ 1/x^{4}= 47, then find the value of x^{3}+ 1/x^{3}1. 18 2. 27 3. 9 4. 12
Sol: (x

^{2}+1/x^{2})^{2}=x^{4}+1/x^{4}+2
so x

^{2}+1/x^{2}=7
(x+1/x)

^{2}=x^{2}+1/x^{2}+2=7+2=9
so x+1/x=3;

now (x+1/x)

^{3}=x^{3}+3*x+3*1/x + 1/x^{3}
3

^{3}=x^{3}+3*3+1/x^{3}
so x

^{3}+1/x^{3}=18
62. If a, b, c are roots of the equation
x

here a=1, b=-4, c=6.5

a

^{3}-4x^{2}+6.5x + 3.5 = 0, then what is the value of a^{2}+ b^{2}+ c^{2}? a. 1 b. 64 c. 169 d.3 Sol: let l,m,n be roots of ax^{3}+bx^{2}+cx+d=0; then l+m+n=-b/a, lmn=-d/a, lm+mn+ln=c/a,here a=1, b=-4, c=6.5

a

^{2}+b^{2}+c^{2}= (a+b+c)^{2}-2(ab+bc+ca)=3.
63. If 1

^{3}+ 2^{3}+ 3^{3}+ ……….+ 9^{3}= 2025 ,then the value of (0.11)^{3}+ (0.22)^{3}+ ….+ (0.99)^{3}is ?
Sol: (11/100)

take (11/100)

(11/100)

^{3}+(22/100)^{3}+ ......(99/100)^{3}take (11/100)

^{3}as common then(11/100)

^{3}[1^{3}+2^{3}+3^{3}+ .....+9^{3}]
=(11/100)

^{3}*2025= 2.695275
64. In a purse there are 30 coins,
twenty one-rupee and remaining 50-paise coins. Eleven coins are picked
simultaneously at random and are placed in a box. If a coin is now picked from
the box, find the probability of it being a rupee coin? Op 1: 4/7 Op 2: 1/2 Op
3: 2/3 Op 4: 5/6 Op 5:

Sol: 2/3

65. A ,B, C are three students who
attend the same tutorial classes. If the Probability that on a particular day
exactly one out of A and B attend the class is 7/10,Exactly one out of B and C
attends is 4/10 exactly one out of A and C attends is 7/10.if the probability
that all the three attend the class is 9/100 then find the probability that all
at least one attends the class.

Sol: Probability(at least one attending
) = 1- Probability(none attending)

Let the Probability of A,B,C attending the class be a,b,c

So not attending will be 1-a,1-b,1-c

Exactly one of A,B

a(1-b) + b(1-a) = 7/10

a+b -2ab =7/10

B,C

b(1-c)+c(1-b) = 4/10

b+c -2bc =4/10

C,A

a(1-c) + c(1-a) =7/10

c+a -2ac=7/10

Add all 3 u get

2(a+b+c) - 2(ab+bc+ca) = 18/10

a+b+c -ab -bc-ca =9/10

P(atleast one ) = 1 - P(none)

1 - [ (1-a)(1-b)(1-c)]

1- [ 1 -a -b-c+ab+bc+ca -abc]

1-[1 - (9/10 + 9/100)]

= 99/100

Let the Probability of A,B,C attending the class be a,b,c

So not attending will be 1-a,1-b,1-c

Exactly one of A,B

a(1-b) + b(1-a) = 7/10

a+b -2ab =7/10

B,C

b(1-c)+c(1-b) = 4/10

b+c -2bc =4/10

C,A

a(1-c) + c(1-a) =7/10

c+a -2ac=7/10

Add all 3 u get

2(a+b+c) - 2(ab+bc+ca) = 18/10

a+b+c -ab -bc-ca =9/10

P(atleast one ) = 1 - P(none)

1 - [ (1-a)(1-b)(1-c)]

1- [ 1 -a -b-c+ab+bc+ca -abc]

1-[1 - (9/10 + 9/100)]

= 99/100

66. A box contains 10 balls numbered 1
through 10. Anuj, Anisha and Amit pick a ball each, one after the other, each
time replacing the ball. What is the probability that Anuj picks a ball
numbered less than that picked by Anisha, who in turn picks a lesser number
than amit.

Sol:

67. A, B, C, D and E play the following
game. Each person picks one card from the cards numbered 1 through 10. The
person who picks the greatest numbered card loses and is out of the game. Now
the remaining four return their cards to the pack and draw again, and again the
person with the greatest numbered card loses. This process is repeated till
only one person is left in the game that is declared the winner. What is the
probability that A is the

winner?

Sol: Ans:1/5

Total five persons so anybody can be the
winner.

68. a buy clips at 12 for R.s. 60 .How
many clips should he sellfor Rs. 60 to earn a profit of 20% ?

Sol: x+0.2x=60;

x=50;

12 clips for 60

so 10 clips for 50.

ans:10

69. An article was sold for Rs. 2770.
Had it been sold for Rs. 3000 there would have been an additional gain of 10%.
Cost Price of the article is:

Sol: given selling price is = 2770

he said if we sell it for 3000 there would be a 10% more gain

3000-2770=230

because of this Rs.230 he can gain 10% more

from profit percentage formula

230*100/ cost price =10

from the above equation cost price is 2300

he said if we sell it for 3000 there would be a 10% more gain

3000-2770=230

because of this Rs.230 he can gain 10% more

from profit percentage formula

230*100/ cost price =10

from the above equation cost price is 2300

70. The probability that a man can hit a
target is 3/4. He tries 5 times. The probability that he will hit the target at
least three times is:

Sol: Hitting the target at least 3 times
means it can be greater than 3 also i.e.3,4,5

in 5 chances hitting target by 3 times is

5c3*(3/4)^3*(1/4)^2 = 10*27/1024= 270/1024

probability of hitting by 4 times is

5c4*(3/4)^4(1/4)^1=5*81/1024= 405/1024

probability of hitting 5 times is

5c5*(3/4)^5 = 243/1024

total is (270+405+243)/1024= 918/1024

=459/512

in 5 chances hitting target by 3 times is

5c3*(3/4)^3*(1/4)^2 = 10*27/1024= 270/1024

probability of hitting by 4 times is

5c4*(3/4)^4(1/4)^1=5*81/1024= 405/1024

probability of hitting 5 times is

5c5*(3/4)^5 = 243/1024

total is (270+405+243)/1024= 918/1024

=459/512

71. A 5-digit number is formed by the
digits 1,2,3,4 and 5 without repetition. What is the probability that the
number formed is a multiple of 4?

Sol:
any number is divisible with 4 iff last two digits should be divisible
with 4.

so if last digit is 2 then 12, 32 and 52
can be last two digits. so 3* 3!

if last digit is 4 then only possibility
is 24 so 3!

total= 3* 3! + 3!= 4!

so 4!/5!=1/5

72. In how many ways can a number 6084
be written as a product of two different factors ?

Sol: 6084 = 6 * 1014 = 6*6*169 = 2

So the pairs will have either 0,1, or 2 powers of each of three prime numbers. But one of these has two identical numbers, and the rest come in pairs of duplicates.

The answer is ((3*3*3)-1)/2 + 1= 13.

^{2}* 3^{2}* 13^{2}So the pairs will have either 0,1, or 2 powers of each of three prime numbers. But one of these has two identical numbers, and the rest come in pairs of duplicates.

The answer is ((3*3*3)-1)/2 + 1= 13.

73. A lady gives dinner party to five
guests to be selected from 9 friends .The number of ways of forming the party
of 5,given that two of the friends will not attend the party together is

Sol: No of guests to be invited=5

Therefore,

No of ways forming the party= (9-2)c5*2c0+(9-2)c4*2c1 =7c5*1+7c4*2 =91

Therefore,

No of ways forming the party= (9-2)c5*2c0+(9-2)c4*2c1 =7c5*1+7c4*2 =91

74. There are 5 letters and five
addressed envelops. the number of ways in which all the letters can be put in
wrong envelops is:

Sol: We have N letters and N envelopes.
The Letters can be put in the N envelopes in N! ways . We want to count the
Number of "Derangements" ( The no. of ways that no letter goes into
right envelope ).

N!( 1- 1/1! + 1/2! - 1/3! +..................+(-1)n 1/n! ) (this the the formula).

Here N = 5.

So When We put N = 5 in Formula we get 44 ans.

N!( 1- 1/1! + 1/2! - 1/3! +..................+(-1)n 1/n! ) (this the the formula).

Here N = 5.

So When We put N = 5 in Formula we get 44 ans.

75. A five -digit number divisible by 3
is to be formed using numerals 0,1,2,3,4 and 5 without repetition. The total
number of ways this can be done is:

Sol: we have 5 place to arrange this no.
and the total should be divisible by 3

no. are :- 0,1,2,3,4,5

take five no.

0+1+2+3+4=10(not divisible by 3)

1+2+3+4+5=15(divisible by 3) possible combination 5!=120

2+3+4+5+0=14(not divisible by 3)

3+4+5+0+1=13(not divisible by 3)

4+5+0+1+2=12(divisible by3)

so these no. we can take, but remember that we can not take 0 at 1st place so

posible combination is 4*4*3*2*1=96

5+0+1+2+3=11(not divisible by 3)

total no.is=120+96=216

no. are :- 0,1,2,3,4,5

take five no.

0+1+2+3+4=10(not divisible by 3)

1+2+3+4+5=15(divisible by 3) possible combination 5!=120

2+3+4+5+0=14(not divisible by 3)

3+4+5+0+1=13(not divisible by 3)

4+5+0+1+2=12(divisible by3)

so these no. we can take, but remember that we can not take 0 at 1st place so

posible combination is 4*4*3*2*1=96

5+0+1+2+3=11(not divisible by 3)

total no.is=120+96=216

76. Mark price of a good is 45 Rs. If seller
sells it at 42 Rs as discount price and also want 5 % profit then what will be
cost price?

Sol: x+0.05x=42; then x=40

77. In a bag there are 5 white, 8 red, 2
black and 3 blue balls. what is probability that ball picked is red or black?

Sol: Total balls=18; Probability=red/tot + black/tot ; 10/18
=5/9

78. How many 4 digit even no. is
possible by 1,2,3,4 if no one is repeated?

Sol= 3! + 3!
=12

79. log

_{3}9-log_{4}256+log_{5}125=?
Sol: 2-4+3=1;

80. If a=2 & b=1 then log

_{(a+b)}(a^{2}-b^{2})=?
Sol: substitute a= and b=1 in log

_{(a+b)}(a^{2}-b^{2})= log_{3}3=1
81. A coin is tossed 3 times by raju.
what is probability that raju win all three time?

Sol: 1/2 * 1/2 * 1/2 = 1/8

82. If there are 5 different roads to go
into a city then no. of ways to go and back to home?

Sol: 25,if one goes using 1st road,there
are 5 roads to come back.....so 5*5, 25 is the ans

83. probability of finding 9 of hearts
from deck of 52 cards ?

Sol: there is only 1,9 of heart is
present in a deck of 52 cards. so
probability of finding 9 of heart=1/52

84. opposite of ' instigate'

Sol: instigate means get something
started: to cause a process to start.

opposite--- stifle,halt

opposite--- stifle,halt

85. log

_{√6}1296= ?
Sol: log

_{√6}6^{4}= 8;
86. Hemant and Ajay start a two-length
swimming race at the same moment but from opposite ends of the pool. They swim
in lane and at uniform speed, but Hemant is faster than Ajay.They first pass at
a point 18.5 m from the deep end and having completed one length, each one is
allowed to rest on the edge for exactly 45 seconds.After setting off on the
return length, the swimmers pass for the second time just 10.5 m from the
shallow end.How long is the pool?

Sol:

87. A and B start together from the same
point on a circular track and walk in the same direction till they both again
arrive together at the starting point. A completes one circle in 224 s and B in
364 s. How many times will A have passed B?

Sol: 13 times; LCM
of 224,364=2912; so, A does 13 circles
while B does 8 in 2912s.

Thus A crosses B 13 times.

Thus A crosses B 13 times.

88. What is opposite meaning of--
DISCREET?

Sol: Discreet means tactful: careful to
avoid embarrassing or upsetting others.

so opposite -- careless

so opposite -- careless

89. The North is a North-East,
North-East is a East, East is a South-East ....then which direction point a
South-East?

Sol: Anticlockwise shift; so south is ans

90. 6:60:: 120:?

Sol: 6+0=6; so 1+2+0=3; so 3 is the answer

91. Log

_{√64}base 8==?
Sol: 1

92. Log

_{2}0.5==?
Sol: Log

_{2}(1/2)= -1
93. Which one used as gobal aparator
from Fuction

1. opaarator:: 2.oparator;; 3.oparator% 4.oparator !! (two bars)

Sol: :: scope resolution operator

94. Which is invalid?

1.10!6 2.false
&& True 3.
bool(x)=(bool)10 4.
flat= 12.67

Sol: flat has no meaning. float will be
decimal point

95. meeru has lost her way t to home and
was standing 25 meters away from her house in the S-W Diraction. she walks 20m
north and reachs Point A . How far and in which direction would she have to
walk to reach her House

1.20 meter.east 2. 15 meter , east 3. 15 meter west 4. 20 meter, west

Sol: 15 meter,east

96. 46:64::82:

1.100 2.104 3.48 4. 42

Sol: 100

97. Q. A __________ is a constructor
that either has no parameters, or if it has parameters, all the parameters have
default values.

A. default constructor B. copy constructor C. Both A and B D. None
of these

98. if 15 oxen or 20 cow can eat the
grass opf the field in 80 days. then in how many days will 6 oxen and 2 cows
eat the same grass. 1.40 2.60 3. 100 4. 160

Sol: 15 oxen take 80 day so, 6 oxen take
15*80/6 =200 day

20 oxen also take 80 day so, 2 cow take 20*80/2 =800 day

together work will be 800*200/(800+200) =160 days

20 oxen also take 80 day so, 2 cow take 20*80/2 =800 day

together work will be 800*200/(800+200) =160 days

99. 754:310::976:??

1.565 2.654 3.643 4.854

Sol: There should be 532;

but a/c to options, 754-310=444;

976-643=333;

so 643 may be an answer

but a/c to options, 754-310=444;

976-643=333;

so 643 may be an answer

100. Which is more-successive discount
of 40% of 30 % OR flat 70% ?

Sol: flat 70%;

because on Rs. 100 ,

successive discount of 40% of 30 %=100*0.6*0.7=42;

flat 100*0.3=30,

so discount of 70% is more

because on Rs. 100 ,

successive discount of 40% of 30 %=100*0.6*0.7=42;

flat 100*0.3=30,

so discount of 70% is more

101. If log(base p)25p=2.Find the value
of P?

Sol: p

^{2}=25*p so p=25;
102. 49 pumps can empty a reservor 6 1/2
days, working 8 hours a day. if 196 pumps are used for 5 hours a day , then the
same work will completed in. 1.
2.6 days 2. 3 days 3. 2.5 days 4. 2 day

Sol: 49*13/2*8=196*x*5

x=2.6 days

x=2.6 days

103. If 7 spider make 7 webs in 7 days
then 1 spider will make 1 web in how many days? 1.1 2.7
3. 7/2 4.49

Sol:
7 Days

104. Ravi brought 300 liter of milk at
Rs 19 per liter. he added 200 liter ofd water to it and sold 400 of milk at rs
20 per liter.to the rest, he added 10 liter more water to it and then sold it
for rs. 15 per liter.if he used miniral water that cast iRs 10 per liter.then
the money earned by ravi is: 1. 4000 2.4500 3.1800 4.1850

Sol: total cost price will be.. (300*19
+ 210 *10 )as 300 lt of was purachsed @ rs 19 and 210 lts of water is added @
rs 10. sp will be , (400*20 + 110 *15 )

so CP = 7800 & SP = 9650

profit = 9650 -7800 = 1850

so CP = 7800 & SP = 9650

profit = 9650 -7800 = 1850

105. 2

^{x+y}=2*(2)^{1/2}and 2^{x-y}= 2^{1/2}, the value of x is. 1.1 2.2 3.3 4.4 5.none of these
Sol: as compare the powers of both eq's

such that x+y= 3/2; x-y=1/2; on solving x=1

such that x+y= 3/2; x-y=1/2; on solving x=1

106. whats the value 1%(modulus)
160/130; 1.160/130 2.1/130 3.1/160 4.
130/160

Sol: 1 %160/130

ie % having higher priority compare to /

so it is calculated as (1%160)/130

so 1/130

ie % having higher priority compare to /

so it is calculated as (1%160)/130

so 1/130

107. FIND THE SERIES: 2,12,36,80,150,__

Sol: 1^2 + 1^3 = 1+1=2

2^2 + 2^3 = 4+8=12

3^2 + 3^3 = 9+27=36

4^2 + 4^3 = 16+64=80

5^2 + 5^3 = 25+125=150

so the next number will be

6^2 + 6^3 = 36+216=252

2^2 + 2^3 = 4+8=12

3^2 + 3^3 = 9+27=36

4^2 + 4^3 = 16+64=80

5^2 + 5^3 = 25+125=150

so the next number will be

6^2 + 6^3 = 36+216=252

108. if RESULT is coded as SFTVMU then
EXAM is coded as_____

Sol: answer is FWBN

adding one to every alphabet to get the next one.

adding one to every alphabet to get the next one.

109. revati brought a machine of
4,50,000 and sold it to raghu at profit . Raghu sold the machine to danush at
loss of 10% for 4 95 000 . wt profit got revati ?

Sol: raghu's cp is revati's sp.

raghu's cp= (100/90)*4,95,000= 550000.

profit %= (100000/450000)*100= 22.22.

answer is 4. 22.22%

110. what is prabablity to getting at
least one of tail . when two coins are tossed simultaineouly?

Sol:3/4

111. (789101112131415x)/8 leaves a
reminder of of 0 .wts th value of x?

Sol: when last 3 digit number is
divisible by 8, then the number is divisible by 8

ans== 2

ans== 2

112. in out of 52 cards, 4 cards to be
are selected and one card of it should be spade and one card card should be
heart. in How many ways can these card selected

Sol: There are 13 spades and 13 heart
cards in pack of 52

we need to select 4 cards and one is from spades and one is from hearts and remaining 2 are form remaining cards

ie 13c1 * 13c1 * 50c2

13^2*50c2

we need to select 4 cards and one is from spades and one is from hearts and remaining 2 are form remaining cards

ie 13c1 * 13c1 * 50c2

13^2*50c2

113. In the
election, the wining candidate won by 15% of votes. if a total 5000 votes were
cast of which is 86% where eligible. then how many votes the wining candidate
get?

Sol: 86% votes
are eligible in 5000

so the number of votes are 5000*86/100=4300

now if loss candidate get x votes then winning one gets 15%more than that of x

ie the total votes is equal to the winning and loss candidate votes

x + (x*115/100)= 4300

from it x = 2000

now we need to calculate for winning candidate

ie x*115/100 = 2000*115/100 = 2300

so the number of votes are 5000*86/100=4300

now if loss candidate get x votes then winning one gets 15%more than that of x

ie the total votes is equal to the winning and loss candidate votes

x + (x*115/100)= 4300

from it x = 2000

now we need to calculate for winning candidate

ie x*115/100 = 2000*115/100 = 2300

114. 47,322 bulb
are to be packed in several boxes. Each box should contains equal Numbers of
bulbs and no bulb should be unpacked number of boxed used can be:

1. 12 2. 11 3. 8 4. 14

Sol: Only 11
can divide the given number.

115. How many 4
digit number can we made from 1 2 3 4 5 6 and 7 with none of digits being
repeated?

Sol: 7*6*5*4=840

116. what is
the value of (10101)

_{2}in decimal form
Sol: 21

117. Wts is
price of a pair of sandles is decreased by 10% the number of pair sold incresed
by 20%. wt is nxt effect on sells?

1.8% decreases 2.10% decreases 3.10% increases 4.
8% increases

Sol: let price
of sandles is x= 100rs.

price is decreased by 10%; x=90rs;

now it is increased by 20%; x=x + 20%(90)

x=90+18; x=108; means increases 8%;

price is decreased by 10%; x=90rs;

now it is increased by 20%; x=x + 20%(90)

x=90+18; x=108; means increases 8%;

118. What is
the value of log

_{7}(1/49)
Sol: -2

119.
18.3454545nis equalent to;

1 1009/55 2.1009/99 3.342/990 4. 345/99

Sol: option 1.

120. price of
salt is increased by 25% in order not to increase the expenditure a lady must
reduce her consumption by:

Sol: let's say lady need 1 salt packet per month
and cost is 100 rupees

now salt packet
rate is increased by 25% so new price will be 125.

but lady should
not increase the expenditure, then how much she can buy with 100 rupees=
100/125

rate of
decrease is given by ((1-
(100/125))1)*100 = 20

121. How money
factors does 400 have?

Sol: 15

122. What is
square root of 54 05 625?

Sol: use square
root division method.... taking groups of 5 40 56 25

ans is :2325

ans is :2325

123. Not a
keyword in exception handling?

1. try 2. rethrow 3.catch 4.access

Sol:access

124. log

_{4}2+log_{4}32 is equals to
Sol: 4

125. product of
any two odd numbers is:

a.always odd b.always even c.sometimes odd and same times even d.divisible
by 6

Sol: (a)

126. A 8-bit
signed integer has the following range:

a. 0 to 255 b. -128 to 127 c. -255 to 254 d. 0 to 509

Sol: (b)... -2

^{(n-1)}to 2^{(n-1)}-1
127. Conceal

**a. Hide**b. Seal c. Ceiling d. Horrifying
128. Vinod took
his meals after he . . . .

a.

**Had completed his work**b. Had been completing his work c. Was completing his work
d. Had been
completed his work e. Had got
completed his work

129. SOLICITUDE

a. insouciance b. ingenuity c. propriety d.
austerity

130. what is
next number in the below series?

8,8,15,23,38,?

Sol: Ans:54

8 8 15 23 38

first diff=0 7 8 15

second diff=7 1 7 1

15+1=16 16+38=54

8 8 15 23 38

first diff=0 7 8 15

second diff=7 1 7 1

15+1=16 16+38=54

131. Wt is
largest and smallest value no divisible by 6,15,21 and 24

a.9235,420 b.9980,840 c.9240,840 d.9999,999

Sol: take lcm
of the numbers 6,15,21,24

ie we will get smallest number 3*2*4*5*7=840

now check the answers

b,c are having 840 so take option which is having higher number and divisible by 840

if its divisible it is its largest if not then option c

840*11=9240

ans : C

ie we will get smallest number 3*2*4*5*7=840

now check the answers

b,c are having 840 so take option which is having higher number and divisible by 840

if its divisible it is its largest if not then option c

840*11=9240

ans : C

132. In How
many ways can a panel of 5 students to be seleted from 8 kids .if a particular
student in complexicity included?

Sol: as one
student is to be included left is 7 from 8 and need to make choice from 4,i.e
7c4 =35

133. Jaya
Brought a worth Rs 3 50 000 four years ago. if the value of the car is
depreciates over time at fixed rate of 10% per annum then what willl be present
worth of car.

Sol: each year
decreses by 10% and for continuous 4years

so 350000*(90/100)*(90/100)*(90/100)*(90/100)=229635

so 350000*(90/100)*(90/100)*(90/100)*(90/100)=229635

134. riya sold
her car for 50000 less than wt she brought it for and lost 8% at what price
should she have sold her car, if she wanted to gain as much as she lost in the
first transaction?

Sol: let
origional price of car is x

x*8/100=50,000

x=625000

s.p=625000+50000=675000

x*8/100=50,000

x=625000

s.p=625000+50000=675000

135. What is
value of 1

^{34}
136. In an
annual sale there was a flat discount of 40 on all items kamal bought a pair of
jeans for rs 480 what is labelled price of the pair of jeans.?

Sol: Let
labeled price be =x

discount =40%

therefore

x-(40% 0f x)=480

x-(40*x/100)=480

x-(2x/5)=480

3x/5=480

x=800

option A)799

discount =40%

therefore

x-(40% 0f x)=480

x-(40*x/100)=480

x-(2x/5)=480

3x/5=480

x=800

option A)799

137. full form
of MIME is:

Sol: MIME:
Multipurpose Internet Mail Extensions

a specification for formatting non-ASCII messages so that they can be sent over the Internet. Many e-mail clients now support MIME,

a specification for formatting non-ASCII messages so that they can be sent over the Internet. Many e-mail clients now support MIME,

138. Synonym of
Vent is:

Sol: vent:
opening, aperture, pore, aditus, aperture

Gate, orifice, valve, vent, stoma, aperture

Gate, orifice, valve, vent, stoma, aperture

139. which is not a data type: 1.boolean 2.array 3.float 4.char

Sol: array

is a temporally storage ,that can store different type of data type vlues

is a temporally storage ,that can store different type of data type vlues

140. Merge sort uses

1.Divide and conquer strategy 2.Backtracking approach 3.Heuristic search 4.Greedy approach

Sol: Quick sort and Merge sort use Divde
and conquer rule

141. find the remainder when 54

^{124}is divided by 17?
a.4 b.5 c.13 d.15

Sol: answer: 4

Rem((54)^124/17)

= Rem((3)^124/17)

=Rem((3^5)^24*(3^4)/17)

=Rem((5)^24*(13)/17)

=Rem((5^3)^8*(13)/17)

=Rem((6)^8*(13)/17)

=Rem((6^4)^2*(13)/17)

=Rem((4)^2*(13)/17)

=Rem((16*13)/17)

=Rem((208)/17)

= 4

Rem((54)^124/17)

= Rem((3)^124/17)

=Rem((3^5)^24*(3^4)/17)

=Rem((5)^24*(13)/17)

=Rem((5^3)^8*(13)/17)

=Rem((6)^8*(13)/17)

=Rem((6^4)^2*(13)/17)

=Rem((4)^2*(13)/17)

=Rem((16*13)/17)

=Rem((208)/17)

= 4

142. Preorder is:

**1. depth first order**2.breadth first order 3.topological order 4.linear order
143. As a part of the maintenance work
you are entrusted with the work of rearranging the library books in a shelf in
proper order, at the end of each day the ideal choice will be;

a. buuble sort

**b. insertion sort**c. selection sort d. heap sort
144. Which of the following is not a
type of constructor?

A. Copy constructor

**B. Friend constructor**C. Default constructor D. Parameterized constructor
145. A firework suddenly . . .
unexpectedly.

(1) fired off (2) went off

**(3) blew off**(4) broke up
146. DISTANCE : MILE

**(1) liquid : pint**(2) weight : scale (3) ton : iron (4) well : water

147. SUPRESS

**(1) stimulate**(2) curb (3) allay (4) redress
148. CONFUSE

**(1) puzzle**(2) orthodox (3) sink (4) gratitude
149. if X% of a is same as y% of b, then
z% of b is

a. (xy/z) % of a b. (yz/x) % of a c.
(xz/y) % of a d. none of
these

Sol: x*a/100=y*b/100

b=x*a/y

then,

z%b=z*b/100=(z*x*a/y)/100=(xz/y) % of a

b=x*a/y

then,

z%b=z*b/100=(z*x*a/y)/100=(xz/y) % of a

150. Each question consists of four
parts of a single sentence; these four parts need to be put in the right order
to form a single, sensible sentence. Choose the option that provides the
accurate ordering of the parts.

A. for the rights of the common man B. they thought it would be questionable

C. while simultaneously fighting D. to lead a privileged urban
lifestyle,

Choose one answer.

a. CADB b.
BCDA

**c. CABD**d. BDCA
151. By ------- the ire of the school
bully after she tripped him in the hall, Shreya ------- months of insults and
teasing.

Choose one answer.

a. protecting . . inhibited b. supplanting . . disguised c. limiting . . satisfied d. provoking . . invited

Sol: d. Provoking...Invited here this
two words used in the sense of Call forth(emotions, anger) and receive

152. meaning of PRODUCT

1.resource

**2.result**3. 4.
153.meaning of CEASE 1.hold

**2.stop**3.retain 4.
154. Log

_{5 }0.2 is equal to: -1
155. hair,pair,fair,lair .... odd man out?

Sol: lair bcz its a place for hiding

156. What is the minimum no of stack of
size n is needed to make a queue of size n?

1.One

**2.Two**3.Three 4.Four
157. For true false a which data type is useful:

**1.boolean**2.float, 3.int 4.char
158. 9,3,6,18,36, .. next no of series:

Sol: 12l;

(9,3) (6,18) (36,12)

9/3=3; 6*3=18; 36/3=12

(9,3) (6,18) (36,12)

9/3=3; 6*3=18; 36/3=12

159. 6,3,18,36... next digit of no;

Sol: 6+3 = 9+9 =18

6+3+18 = 27+9 =36

6+3+18+36=63+9 =72

6+3+18 = 27+9 =36

6+3+18+36=63+9 =72

160. what is the remainder when 2^21 is
divided with 6?

Sol: 2^21 / 6; =
(2^3)^7 / 6; = (6+2)^7
/ 6; = 2^7 / 6; = 128 / 6 gives rem = 2; rem = 2

161. if lcm of 2 nums is 729 then hcf?

Sol: 729=9x9x9

so ,lcm of 1 and 729=729,lcm of 3 and 729=729,lcm of 9 and 729=729......so on

so hcf will also vary accordingly.

Data insuficient.

so ,lcm of 1 and 729=729,lcm of 3 and 729=729,lcm of 9 and 729=729......so on

so hcf will also vary accordingly.

Data insuficient.

162. ABCD=12; TALE=8;
THEN DREAM=????

Sol: The solution is (No of
consonant)*(Total No of Alphabet)

ABCD= 3*4=12; TALE= 2*4=8; so

DREAM = 3*5 = 15 (ANS.)

ABCD= 3*4=12; TALE= 2*4=8; so

DREAM = 3*5 = 15 (ANS.)

163. A GARRISON HAS SUFFICIENT FOOD FOR
75 SOLDIERS FOR A PERIOD OF 90 DAYS.AFTER 10 DAYS,ONE THEIRD OF THE SOLDIERS
LEAVE.AFTER ANOTHER 10 DAYS,5 SOLDIERS RETURN FROM THIS DAY ON,HOW MANY DAYS
WILL THE FOOD LAST ?

Sol: Intially there are 75 Soldiers and
food for 90 days...

After 10days food remains for 80days and 75 soldiers so

75*80=D*50(since after 10 days soldiers become 2/3)

we get D=120

Now food remains for 120days for 50 Soldiers

Again after 10days

50*110=D*55

D=100days

After 10days food remains for 80days and 75 soldiers so

75*80=D*50(since after 10 days soldiers become 2/3)

we get D=120

Now food remains for 120days for 50 Soldiers

Again after 10days

50*110=D*55

D=100days

164. P, Q and S are moving on a circular
stadium of circumference 2100 m. When P completes one round, Q is still 700 m
behind. When S completes one round, Q is 300 m ahead of him.What distance from
the starting point Q covers when three of them will meet for the first time ?

Sol: when s completes 7 rounds ...then q
completes 8 round....(from 2nd statement) and

when p completes 3 rounds ...then q completes 2 round....(from 1st statement)

so when q completes 8 rounds then p completes 12 rounds and s completes 7 rounds.

so q covers 8*2100=16800m....(ANS)

when p completes 3 rounds ...then q completes 2 round....(from 1st statement)

so when q completes 8 rounds then p completes 12 rounds and s completes 7 rounds.

so q covers 8*2100=16800m....(ANS)

165. A man earns Rs. 24,000 pm. He
spends 1/3rd of his income on personal expenditures. Half of the remaining
income is invested in a scheme at 15% interest pa. After investing, half of
what is left is invested in a scheme which gives 10% interest pa. The remaining
lies in a bank, where it earns an interest of 4% pa. The effective rate of
interest earned by the man on his investments at the end of the year is ?

Sol: amount remaining=
24000-24000/3=16000

1. 16000/2=8000 SI=PRT/100=8000*15*1/100=1200

2. 8000/2=4000 SI=4000*10*1/100=400

3. 4000 SI=4000*4*1/100=160

adding total interest=1200+400+160=1760

SI=PRT/100 1760=16000*R*1/100

Solving this R=11% Ans......

1. 16000/2=8000 SI=PRT/100=8000*15*1/100=1200

2. 8000/2=4000 SI=4000*10*1/100=400

3. 4000 SI=4000*4*1/100=160

adding total interest=1200+400+160=1760

SI=PRT/100 1760=16000*R*1/100

Solving this R=11% Ans......

166. A company needs to choose a team of
4 from a group of 3 content managers, 3 R&D engineers and 5 client
engagement managers for the completion of a project. What is the probability
that exactly 3 of them are client engagement managers?

Sol: Total members = 3+3+5 = 11

Total no. of ways of selection 4 members is 11C4 = 330

No. of ways of selecting exactly 3 client eng managers are

3 from client (AND) 1 from content managers

(OR)

3 from client (AND) 1 from R&D

=> 5C3*3C1 + 5C3*3C1 = 30 + 30 = 60

Prob. ll be 60/330 = 2/11

Ans : 2/11

Total no. of ways of selection 4 members is 11C4 = 330

No. of ways of selecting exactly 3 client eng managers are

3 from client (AND) 1 from content managers

(OR)

3 from client (AND) 1 from R&D

=> 5C3*3C1 + 5C3*3C1 = 30 + 30 = 60

Prob. ll be 60/330 = 2/11

Ans : 2/11

167. It took me a while to _______ to
the new job

**a. adapt**b refresh c renew d dismiss

168. these clothes are very nice,but the
are terribly ________________

a ugly

**b overpriced**c desired d adorable
169. A Vehicle and an engine have a
________________________.

A) Is – A relationship

**B) Has – A relationship**C) No relationship D) Polymorphic relationship
170. Which of the following statement is
true?

A) A link list is a collection of
structure a ordered by their physical placement

in memory like an array

B) The double linked lists have no
beginning and no end

C) A stack is a buffer in which data
items are retrieved in reverse order from

which they are placed in the buffer

D) None of the above

Sol: Ans : C) A stack is a buffer in
which data items are retrieved in reverse order from which they are placed in
the buffer

Stack follows Last in First Out (LIFO) principle... So data ll be retrieved in reverse order...

(A) is not true since linked list is not like arrays..

Stack follows Last in First Out (LIFO) principle... So data ll be retrieved in reverse order...

(A) is not true since linked list is not like arrays..

171. What is the output of following
program?

int main()

{

char
boolean[][6]={"TRUE","FALSE"};

printf("%s",boolean[(unsigned
int)-1 == ~0]);

}

A) 0 B)
1 C) FALSE D) Run time error

Sol: False

Here (unsigned int)-1 means converting -1 to an equivalent unsigned integer value i.e the max value of unsigned int.

The bitwise complement operator, the tilde, ~, flips every bit.

~0 means all 0 bits are flips to 1 then here also we get same value as above i.e max value of unsigned int.

Finally (unsigned int)-1== ~0 becomes true and it displays FALSE

Here (unsigned int)-1 means converting -1 to an equivalent unsigned integer value i.e the max value of unsigned int.

The bitwise complement operator, the tilde, ~, flips every bit.

~0 means all 0 bits are flips to 1 then here also we get same value as above i.e max value of unsigned int.

Finally (unsigned int)-1== ~0 becomes true and it displays FALSE

172. This brand of TV is quite
inferior_____ that one.

A) than

**B) to**C) with D) over
173. The stenographer is very efficient.
He is ______ to his firm.

**A) an asset**B) a credit C) a blessing D) a boon

174. Today _____ the inaugural day of
the pub, the drinks were served free of cost.

Was Been Is Being

Sol: being.

see the verb "were served"

see the verb "were served"

175. 1) 7^a+4* 5^b=1715 value of ab=

Sol: 7^(a+4)* 5^b = 1715 = 343*5 = 7^3 *
5^1

=> a+4=3 & b=1

=> a=-1 & b=1

=> ab = -1

=> a+4=3 & b=1

=> a=-1 & b=1

=> ab = -1

176. 2) if ab,c are gp then loga, logb,
logc are in

a) ap b)
gp c) hp d) None

Sol: a,b,c are in GP

=> b^2 = c*a

taking log both sides

=> 2*logb = logc + loca

if x,y,z are in AP, then 2y=x+z

=> loga,logb,logc are in AP.

=> b^2 = c*a

taking log both sides

=> 2*logb = logc + loca

if x,y,z are in AP, then 2y=x+z

=> loga,logb,logc are in AP.

177. synonym of musty= =smelly

178.antonym of ignite== extinguis

179. Arrays can be initialized provided
they are

(1) Automatic (2) External (3)
Static (4)
Both (2) and (3)

Sol: 1) Automatic

Auto array variables can be initialized...By default all the variables are auto even if it is not declared with "auto" keyword...

Auto array variables can be initialized...By default all the variables are auto even if it is not declared with "auto" keyword...

180. In C programming language x – = y +
1 ; means

(1)x= x-y+1 (2)x=-x-y-1 (3)x=-x+y+1

**(4)x= x-y-1**
181. Recursive function are executed in
a

(1) Last in fIrst out order (2) First in fIrst out order (3) Parallel fashion (4) All of the above

Sol: Recursive functions uses System
Stack which is typically Last-In-First-Out (LIFO) data structure. Hence the
last recursive call return the control and/or value first.

Ans: (1) Last In First Out order

Ans: (1) Last In First Out order

182. The void specifier is used if a
function does not have return type.

A. True
B. False

Sol: A. True

"Void" keyword doesnt return any value... So its used if a function doesnt have return type....

"Void" keyword doesnt return any value... So its used if a function doesnt have return type....

183. What is the only function all C++
programs must contain?

A. start() B. system() C.main() D.program()

Sol: (C) main()

Every programming language must contain "main()" function to execute any block of code...

Every programming language must contain "main()" function to execute any block of code...

184. What is the correct value to return
to the operating system upon the successful completion of a program?

A. -1 B.
1 C.0 D.Programs do not return a value

Sol: (c) 0 ; Normal exit is generally represented by a 0
return value from main. Abnormal termination is usually signalled by a non-zero
return but there is no standard for how non-zero codes are interpreted.so
answer is (c)

185. In which of the following
scheduling policies does context switching never take

place? A)
Round-robin

**B) Shortest job first**C) Pre-emptive D) All of the above
186. The average weight of 8 persons
increases by 2.5kg when a new person comes in a place of one of them weighing
45kg.what is the weight of the new person??

Sol: total weight
increased=(2.5kg*8)=20kg

weight of the new person=(45+20)=65kg

ans:w=65kg

weight of the new person=(45+20)=65kg

ans:w=65kg

187. Tushar was studying about the
network topology of his company. He asked one of his colleagues to guess the
right topology on the following clues: 1. The topology used is point to point
configured. 2. The topology provides fault isolation property. 3. If one link
becomes unusable, then whole system is not incapacitated

Sol: Its Mesh Topology...

Its point to point configured

If one link becomes unusable,the whole system is not incapacitated

It supports fault identification and fault isolation property

Its point to point configured

If one link becomes unusable,the whole system is not incapacitated

It supports fault identification and fault isolation property

188. log

_{10}0.001 =?
189. What mustbe subtracted from p
andadded to q so that the ratio of the resultants becomes 1:3?

Sol: let x be the reqd no. then

A/Q

A/Q

(p-x)/(q+x)= 1/3

=> 3p-3x = q+x

=> 4x = 3p-q

=> x = (3p-q)/4

=> 3p-3x = q+x

=> 4x = 3p-q

=> x = (3p-q)/4

190. x,yand z are three quantities.X
varies inversely with Y when Z is constant.Y varies inversely with Z when X is
constant.When Y=8,and Z=7,X=30.Find X if Y=16 and Z=21.

Sol:

191. LCM of two numbers is 120 and their
HCF is 10. Which one of the following be the sum of two numbers?

a) 140 b)
80 c) 60 d) 70

Sol: 70

Let the numbers be x and y

x*y = lcm*hcf = 1200

xy = 1200

Since the hcf of numbers = 10 , the numbers are multiples of 10

Factors of 1200 that are multiples of 10

(120,10),(60,20),(40,30)

Since lcm = 120

numbers are (40,30)

sum of numbers = 30+40=70

Let the numbers be x and y

x*y = lcm*hcf = 1200

xy = 1200

Since the hcf of numbers = 10 , the numbers are multiples of 10

Factors of 1200 that are multiples of 10

(120,10),(60,20),(40,30)

Since lcm = 120

numbers are (40,30)

sum of numbers = 30+40=70

192. A reduction of 20% price of sugar
enables to purchase 5 kg of sugar more for Rs 600. Find the price of the sugar
per kg before reduction.

Sol: let price of sugar = x rs/kg

after 20% reduction, price of sugar is = .8x rs/kg

A/Q

600/.8x - 600/x = 5

=> 600/x (1/.8 -1)=5

=> x = 30

price of the sugar per kg before reduction = 30 rs/kg

after 20% reduction, price of sugar is = .8x rs/kg

A/Q

600/.8x - 600/x = 5

=> 600/x (1/.8 -1)=5

=> x = 30

price of the sugar per kg before reduction = 30 rs/kg

193. 20% loss on selling price is what
percent loss on cost price?

Sol: let sp 100 then 20% loss on sp so
cp is 120

then (20/120)*100 = 16.66%

then (20/120)*100 = 16.66%

194. x sells to article for 4000 each
with no loss and no gain in the interaction. If one was sold at a gain of 25%
and other at sola at a loss of?

a) 25% b)
18 2/9 c) 20% d) 16 2/3

Sol: d)16 2/3%

Explanation:

according to the question each item is sold for rs 4000.So the total selling price of the items is (4000+4000=8000).Since,there is no loss or gain in the entire process

then the total cost price will be equal to the total cost price i.e. 8000.

Now,since the 1st item is sold at a gain of 25% that means its c.p. is given by:

{(4000-c.p.)/c.p.}*100=25 which gives c.p. of 1st item i.e. 3200.since,the total c.p. is 8000 the c.p of the 2nd item is 8000-3200=4800 and the s.p. of 2nd item is 4000 hence the 2nd item is sold at the loss of {(4800-4000)/4800}*100=16 2/3%

Explanation:

according to the question each item is sold for rs 4000.So the total selling price of the items is (4000+4000=8000).Since,there is no loss or gain in the entire process

then the total cost price will be equal to the total cost price i.e. 8000.

Now,since the 1st item is sold at a gain of 25% that means its c.p. is given by:

{(4000-c.p.)/c.p.}*100=25 which gives c.p. of 1st item i.e. 3200.since,the total c.p. is 8000 the c.p of the 2nd item is 8000-3200=4800 and the s.p. of 2nd item is 4000 hence the 2nd item is sold at the loss of {(4800-4000)/4800}*100=16 2/3%

195. What is the probability of start
with T in the word STUDENT

Sol: Total no of ways word STUDENT can
be arranged = 7!/2! = 2520

No of ways STUDENT can be arranged starting with T = 6! = 720

Probability of start with T in the word STUDENT = 720/2520 =2/7

No of ways STUDENT can be arranged starting with T = 6! = 720

Probability of start with T in the word STUDENT = 720/2520 =2/7

196. A manufacturing company produces a
batch of 10 containers out of which 4 are defective. In a quality inspection, 3
containers are chosen at random. What is the probability that at least one is
defective?

Sol: none is defected =(6c3/10c3)=1/6

at least one=1-(1/6)=5/6

at least one=1-(1/6)=5/6

197. If 9x

^{2}+3px+6q when divide by 3x+1 leaves a remainder -3/4 and qx^{2}+4px+7 is exactly divisible by x+1, then the values of p and q respectively will be:
Sol: Ans : p = 7/4, q = 0

Given 9x^2+3px+6q % 3x+1 = -3/4

ie 3x+1 => x = -1/3

|9 3p 6q

-1/3| -3 1-p

******************

9 3p-3 6q+1-p

6q+1-p=-3/4 --> (1)

Similarly qx2+4px+7 is exactly divisible by x+1

means qx2+4px+7 % x+1 = 0

ie x+1 => x= -1

| q 4p 7

-1| -q q-4p

******************

q 4p-q 7+q-4p

7+q-4p = 0

q = 4p - 7 -->(2)

sub q=4p-7 in eq(1)

6q+1-p=-3/4

24p-42+1-p=-3/4

23p = 161/4 => p=161/(23*4)

p=7/4

sub p=7/4 in eq(2)

q=(4*7/4)-7

q=0

Hence p=7/4, q=0

Given 9x^2+3px+6q % 3x+1 = -3/4

ie 3x+1 => x = -1/3

|9 3p 6q

-1/3| -3 1-p

******************

9 3p-3 6q+1-p

6q+1-p=-3/4 --> (1)

Similarly qx2+4px+7 is exactly divisible by x+1

means qx2+4px+7 % x+1 = 0

ie x+1 => x= -1

| q 4p 7

-1| -q q-4p

******************

q 4p-q 7+q-4p

7+q-4p = 0

q = 4p - 7 -->(2)

sub q=4p-7 in eq(1)

6q+1-p=-3/4

24p-42+1-p=-3/4

23p = 161/4 => p=161/(23*4)

p=7/4

sub p=7/4 in eq(2)

q=(4*7/4)-7

q=0

Hence p=7/4, q=0

198. A biased die has a probability of
1/4 of showing a 5, while the probability of any of 1, 2, 3, 4, or 6 turning up
is the same . If three such dice are rolled, what is the probability of getting
a sum of atleast 14 without getting a 6 on any die ?

Sol: (4,5,5)(5,4,5)(5,5,4)(5,5,5)=
3(3/20* 1/4*1/4) + (1/4)

^{3}=7/160
199. A = 1^1 * 2^2 * 3^3 * 4^4 * 5^5 *
……..10^10. How many zeroes will be there at the end of A ?

Sol: 10^10 ---> gives 10 zeros

2*5 = 10

Here in question there are five 5's ( 5^5)

and more then five 2's ( 2^2, 4^4,6^6...)

So we get five more 10's from 2^5*5^5

{ 2^5*5^5 = (2*5)*(2*5)*(2*5)*(2*5)*(2*5)=10*10*10*10*10 = 10^5)

thus there is a total of 15 zeros in the answer.

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2*5 = 10

Here in question there are five 5's ( 5^5)

and more then five 2's ( 2^2, 4^4,6^6...)

So we get five more 10's from 2^5*5^5

{ 2^5*5^5 = (2*5)*(2*5)*(2*5)*(2*5)*(2*5)=10*10*10*10*10 = 10^5)

thus there is a total of 15 zeros in the answer.

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